Poker Dice Winning Hands

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Knowing your poker hands is crucial to playing a solid game at the table, and regardless of whether you’re playing Texas Hold’em, or Omaha, you’ll always want to know the value of your hand. When you have this knowledge at your disposal, you’ll be able to make an informed decision on whether to raise, check, call, or fold your hand when it matters most.

The game of poker is a card game played among two or more players for several rounds. There are several varieties of the game, but they all tend to have these aspects in common: The game begins with each player putting down money allocated for betting. During each round of play, players are dealt cards from a standard 52-card deck, and the goal of each player is to have the best 5-card hand at. The is the best possible hand you can get in standard five-card Poker is called a royal flush. This hand consists of an: ace, king, queen, jack and 10, all of the same suit. If you have a royal flush, you'll want to bet higher because this is a hard hand to beat. Liliboas / Getty Images. The hands under this system rank almost the same as in standard poker. It includes straights and flushes, lowest hand wins. However, this system always considers aces as high cards (A-2-3-4-5 is not a straight.) Under this system, the best hand is 7-5-4-3-2 (in mixed suits), a reference to its namesake. Poker dice, game involving five dice specially marked to simulate a playing-card deck’s top six cards (ace, king, queen, jack, 10, 9). The object is to throw a winning poker hand, with hands ranking as in poker except that five of a kind is high and there are no flushes.

In this post, we’re going to look at the winning poker hands structure of two different games; Texas Hold’em, and Omaha – and we’ll begin by taking a look at a poker hands chart, followed by the best and worst starting hands. We’ll also show you a list of poker hands to help you make the right decisions in your game.

Texas Hold’em Winning Poker Hands Ranking

In this guide, you’ll see that there are a total of 10 hands in Texas Hold’em poker (or 9 if you don’t count ‘no pair’ as a hand), and we’ll detail these below. (The winning poker hands chart below shows a list of poker hands, ranked best, to worst).

Royal Flush: Ten, Jack, Queen, King, Ace, all of the same suit.

Straight Flush: Any 5 cards of the same suit, in consecutive order. (I.e. 5, 6, 7, 8, and 9 of spades).

4-of-a-kind: 4 cards of the same value (i.e. the 5 of spades, the 5 of hearts, the 5 of clubs, and the 5 of diamonds).

Winning

Full House: A full house consists of one 3-of-a-kind hand, and one pair, so for instance, a full house could be the 2 of spades, the 2 of diamonds, the 2 of clubs, and a pair of Aces.

Flush: Five cards of the same suit (i.e. 2, 3, 7, 8, and 9 of hearts).

Straight: Five cards in consecutive order (i.e. 2, 3, 4, 5, 6, off-suit).

3-of-a-kind: Three cards of the same value (I.e. 3 of clubs, 3 or spades, and the 3 of hearts).

Two Pair: Two pairs in one hand – i.e. a pair of 2’s, and a pair of 3’s.

One Pair: One singular pair – i.e. a pair of Aces.

No Pair: A no pair hand is when you don’t have any of the above. In this instance, you have what is known as a ‘high card hard’.

Use the poker hands chart above to ensure you’re always in full control of your game!

Omaha Poker Hands Ranking

Omaha uses the exact same hand-ranking process as Texas Hold’em does, and while it may seem as though that’s a little ‘odd’ at first, remember that Omaha is almost identical, aside from the fact that players have four cards, and that betting is usually pot-limit.

This means that a Royal Flush is the best possible hand in a game of Omaha, and high-card (while incredibly unusual due to the 4 cards each player holds) is the lowest possible hand.

For a full guide on playing Omaha, be sure to check out our How to Play Omaha guide.

Poker dice winning hands wins

Best Starting Poker Hands

Knowing your winning poker hands is crucial if you want to play a solid game of poker – and below, we share how to determine whether or not you have a winner on your hand!

Texas Hold’em: The best starting hand is a pair of Aces. A pair of aces (also known as pocket rockets) are a favourite pre-flop over any other starting hand and is almost always one of the best winning poker hands. The second, and third best starting hands are a pair of Kings and Queens respectively, followed by Ace-King suited, pocket Jacks, pocket Tens, and then Ace-Queen suited. The 10th best starting hand is Ace-King Offsuit – which is actually still a very strong hand.

Cached

Omaha: Working out winning poker hands in Omaha is a little more complex than Texas Hold’em, when looking at the best starting hands, although mathematically, the best starting hands can be determined.

For example, the strongest hand is AAKK, followed by AAJT, AAQQ, and AAJJ. It’s worth noting however, that the best possible hand in Omaha holds little value against a full-ring of players, hence the need to play aggressively, pre-flop and post-flop; see our poker hands chart for more details.

Poker Dice Winning Hands

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Worst Poker Starting Hands

Determining the worst starting hands in poker is a little more challenging – largely due to the fact that most players simply have knowledge of the better starting hands – yet knowing what the worst starting hands are is just as important, as it allows you to know when to throw away your hands pre-flop. Below, we look at the worst starting hands for both Texas Hold’em and Omaha.

Texas Hold’em: 2-7 offsuit (this is well-known as the worst starting hand in poker, due to the fact that it’s often used as side-bets in games.) 7-2 offsuit is followed by 8-2 offsuit, 8-3 offsuit, 7-3 offsuit, 6-2 offsuit, 9-2, 9-3, and 9-4 offsuit.

Python - Find And Display Best Poker Hand - Code Review Stack ...

Omaha: Unfortunately, with Omaha, there isn’t an ‘official’ list of worst poker hands – purely due to the fact that there would be too many to list. However, most professionals and poker experts agree that any starting hand that combines any of the worst starting hands in Texas Hold’em generally constitute a very poor starting hand in Omaha too – so it’s worth throwing these away most of the time, pre-flop. If in doubt, consult the list of winning poker hands ranking above.

Intro

This is a problem concerning basic probability calculations from the text: “A First Course in Probability Theory” by Sheldon Ross (8th addition).

Sample Problem

Poker Dice Winning Hands Wins

Chapter 2 #16. Poker dice is played by simultaneously rolling 5 dice. Show that:
a) P[no two alike] = .0926, b) P[one pair] = .4630, c) P[two pair] = .2315, d) P[three alike] = .1543, e) P[full house] = .0386, f) P[four alike] = .0193, g) P[5 alike]=.0008.

Solution

Poker Dice Winning Hands Against

Notation, I will let ^ designate the power function. For example, 6^5 is 6 to the fifth power. 6! is 6 factorial, 6! = 6 * 5 * 4 * 3 * 2 * 1.
To calculate the Probabilities here, we will divide the number of occurrences for a particular event by the total possibilities in rolling 5 dice.
N[total] = total possibilities in rolling five dice = 6^5 = 7776
Note: N[total] is the number of ordered rolls. For example, if we rolled the dice one by one and rolled in order 3,4,5,6,2, it would be considered as different from if we rolled 2,3,4,5,6 in order.
a) P[no two alike]
There are 6 choices of numbers for the first dice. The 2nd dice must be one of the remaining 5 unchosen numbers, and the 3rd dice one of the 4 remaining unchosen numbers, and so on… This gives an ordered count, so:
N[no two alike] = 6 * 5 * 4 * 3 * 2 = 720
P[no two alike] = N[no two alike]/N[total] = 720/7776 = 0.09259259
b) P[one pair]
First we count the possible sets (unordered) of numbers. Here we have one number that is the pair, 6 choices. Then we must choose 3 different numbers from the remaining 5 values, as these three are equivalent, we have choose(5,3) = 5!/(3! * 2!) possibilities. So 6 * choose(5,3) is the total combinations of numbers. Since we are dealing with ordered counts, we must consider the orderings for each set of numbers. We have 5 die with 2 the same so the number of orderings is 5!/2!. Multiplying these together gives us the number of ordered samples:
N[one pair] = 6 * (5!/(3! * 2!)) * (5!/2) = 3600
P[one pair] = N[one pair]/N[total] = 0.462963
c) P[two pair]
Here we have 2 pairs which are equivalent, so we must choose 2 values from the 6 possible values, choose(6,2)= 6!/(2! * 4!). Then we must choose 1 value from the remaining 4 for the single value, 4 ways. Now we must consider the orderings, 5 die with 2 sets of 2 the same so the number of orderings is 5!/(2! * 2!).
N[two pairs] = (6!/(2! * 4!)) * 4 * (5!/(2! * 2!)) = 1800
P[two pairs] = N[two pairs]/N[total] = 0.2314815
d) P[three alike] (the remaining two cards are different)
There are 6 choices for the three of a kind. Then we must choose 2 different values from the remaining 5 choices, choose(5,2) = 5!/(2! * 3!). The number of orderings is 5 items with 3 being identical, which is 5!/3!.
N[three alike] = 6 * (5!/(3! * 2!)) * (5!/3!) = 1200
P[three alike] = N[three alike]/N[total] = 0.154321
e) P[full house] 3 alike with a pair.
We need one value for the three that are alike, 6 ways, and then we must choose from the remaining 5 values for the pair, 5 ways. The orderings are given by 5!/(3! * 2!).
N[full house] = 6 * 5 * (5!/(3! * 2!)) = 300
P[full house] = N[full house]/N[total] = 0.03858025
f) P[four alike]
We need one value for the four of a kind, and then one value from the remaining 5 for the last die. The number of orderings is given by 5!/4!.
N[four alike] = 6 * 5 * (5!/4!) = 150
P[four alike] = N[four alike]/N[total] = 0.01929012
g) P[five alike]
Here we need 1 value for the five alike, 6 ways. There is just 1 possible ordering as all five die are the same.
N[five alike] = 6
P[five alike] = N[five alike]/N[total] = 0.0007716049
Check: the numbers of each type must sum to N[total] = 7776:
720 + 3600 + 1800 + 1200 + 300 + 150 + 6 = 7776

Extra:
Straight
We can have two possible straights: one composed of (6,5,4,3,2) and one composed of (5,4,3,2,1). Each of these straights can be permuted 5! ways.
N[straight] = 2 * 5! = 240
P[straight] = N[straight]/N[total] = 0.0308642

Now let’s run a simulation in R:

Results of simulation:
notwoalike: 0.09194
onepair: 0.464
twopair: 0.23187
threealike: 0.1554
fullhouse: 0.03727
fouralike: 0.01889
fivealike: 0.00063
straight: 0.03072